x^2-98x+2000=0

Solution for x^2-98x+2000=0 equation:

x^2-98x+2000=0

a = 1; b = -98; c = +2000;
Δ = b2-4ac
Δ = -982-4·1·2000
Δ = 1604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1604}=\sqrt{4*401}=\sqrt{4}*\sqrt{401}=2\sqrt{401}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-98)-2\sqrt{401}}{2*1}=\frac{98-2\sqrt{401}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-98)+2\sqrt{401}}{2*1}=\frac{98+2\sqrt{401}}{2}
$